Question

If f(1) = 2 and f(n+1) = f(n)^2 – 3 then find the value of f(3).

Answer 1

The value of f(3) = -2.

Explanation:

First of all, let's find f(2).

`f(n+1)=f(n)^(2)-3`

`f(1+1)=f(1)^(2)-3`

`f(2)=f(1)^(2)-3=2^(2)-3=1`

Now, we can find f(3):

`f(2+1)=f(2)^(2)-3`

`f(3)=f(2)^(2)-3=1^(2)-3=-2`

Therefore, the value of f(3) = -2.

I hope it helps you!