146k views
4 votes
a rock found in a gold mine weighs 12 ounces.If it contains 14% gold, how many ounces of gold does the rock contain?

User Diogo S
by
7.9k points

2 Answers

5 votes

Answer: 1.68

Step-by-step explanation: So, if we want to find how much gold is in the rock, it's a good idea to set up a proportion. So, it would be like this:


(14)/(100) = (?)/(12)

Now, we would cross-multiply the 12 and the 14, which is 168, and then divide it by 100. That can be found by moving the decimal 2 places left of 168.00. So, that would be 1.68. Therefore, there are 1.68 ounces of gold in the rock. I hope this helped!

User Psanjib
by
8.7k points
2 votes

Answer: 1.68

Step-by-step explanation: Okay, to find this we need to use this formula:

Amount = Part percent * whole number / 100

So, now let's plug in the numbers:

Amount = 14 * 12 / 100

= 168/100

= 1.68

Therefore the amount of gold in the rock is 1.68 oz out of the 12 ounces.

I hope this helped!

User CKT
by
8.2k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories