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2K3N + 3CaCl2 → 6KCl + Ca3N2 1 mol K3N = 131.301 g K3N 1 mol CaCl2 = 110.984 g CaCl2 1 mol KCl = 74.551 g KCl 1 mol Ca3N2 = 148.248 g Ca3N2 How many grams of CaCl2 would it take to make 1.5 moles of KCl?
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3 votes
2K3N + 3CaCl2 → 6KCl + Ca3N2

1 mol K3N = 131.301 g K3N

1 mol CaCl2 = 110.984 g CaCl2

1 mol KCl = 74.551 g KCl

1 mol Ca3N2 = 148.248 g Ca3N2

How many grams of CaCl2 would it take to make 1.5 moles of KCl?

a
110.984 g
b
83.238 g
c
54.213 g
d
166.476 g

User Risingtiger
by
8.0k points

1 Answer

6 votes
The correct choice is B) 83.238 g
2K3N + 3CaCl2 → 6KCl + Ca3N2 1 mol K3N = 131.301 g K3N 1 mol CaCl2 = 110.984 g CaCl-example-1
User Ivan Valadares
by
7.9k points
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