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What is the equation of a line that is perpendicular to the line y = −3x + 2 and passes through the point (6, 8)?

2 Answers

7 votes

Answer:

y = 1/3x + 6

Explanation:

Because perpendicular lines have opposite and reciprocal slopes, we have to change our slope into a positive and flip it into it's reciprocal.

Now its: y = 1/3x + b

Next, we find b using slope intercept form.

8 = 1/3(6) + b

8 = 2 + b

6 = b

Place b into the equation.

y = 1/3x + 6

User Swidmann
by
9.2k points
4 votes

Answer:
y=(1)/(3) x+6

Explanation:

To find the perpendicular line, we have to change the slope of the original, equation.

The slope of the perpendicular line is 1/3. We can plug in the new point. To find the equation.


8=(1)/(3)(6)+b [multiply]

8=2+b [subtract both sides by 2]
b=6

Final equation is
y=(1)/(3) x+6

User Inderpal Singh
by
7.7k points