119k views
4 votes
What is the equation of a line that is perpendicular to the line y = −3x + 2 and passes through the point (6, 8)?

2 Answers

7 votes

Answer:

y = 1/3x + 6

Explanation:

Because perpendicular lines have opposite and reciprocal slopes, we have to change our slope into a positive and flip it into it's reciprocal.

Now its: y = 1/3x + b

Next, we find b using slope intercept form.

8 = 1/3(6) + b

8 = 2 + b

6 = b

Place b into the equation.

y = 1/3x + 6

User Swidmann
by
9.5k points
4 votes

Answer:
y=(1)/(3) x+6

Explanation:

To find the perpendicular line, we have to change the slope of the original, equation.

The slope of the perpendicular line is 1/3. We can plug in the new point. To find the equation.


8=(1)/(3)(6)+b [multiply]

8=2+b [subtract both sides by 2]
b=6

Final equation is
y=(1)/(3) x+6

User Inderpal Singh
by
8.5k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories