Question

On August 20, 1989, in Cologne, West Germany, Said Aouita of Morocco also established a world record when he ran the 3000. m run in 7 minutes, 29.45 seconds. What was his average speed (in m/s) for the race? Remember to include your data, equation, and work when solving problem

PLS HURRY I HAVE TO TURN THUS IN!!!!!

Answer 1

6.67 m/s

Explanation:

7 * 60 = 420

420 + 29.45 = 449.45

V = 3000. / 449.45= 6.67 m/s

Answer 2

Average speed of Aouita = 6.68 meter per second.

Explanation:

To create a world record Aouita ran a distance = 3000 m

He took the time to cover this distance = 7 minutes 29.45 seconds

= (7×60) + 29.45 seconds

= 449.45 seconds

Since, formula for the average speed is given by,

Average speed =
`\frac{\text{Total distance covered}}{\text{Total time taken}}`

Therefor, average speed of Aouita =
`(3000)/(449.45)`

= 6.675

≈ 6.68 meter per second

Average speed of Aouita was 6.68 meter per second.