A-
The diagram of the set up shows the book resting on a horizontal table top with the force of gravity acting on it.
B-
The force acting on the book before the force was applied with the pencil is the force of gravity.
The magnitude of the force of gravity is 2.5n (the weight of the book).
C-
The book is at rest due to the force of friction being equal to the force of gravity. The force of friction is opposing the force of gravity, preventing the book from moving.
D-
The diagram shows the sliding book with the force of friction opposing the applied force of 2n and the force of gravity acting on it.
E-
The acceleration of the book can be calculated by the force acting on it divided by the mass of the book.
a = (Fapplied - Ffriction) / m
a = (2 - 1) / 2.5 = 0.4 m/s^2
The velocity of the book can be calculated using the equation:
v = a * t
v = 0.4 * 1.5 = 0.6 m/s
The book will have a velocity of 0.6 m/s when the applied force has been acting on it for 1.5 seconds.