Question

30. A stone falls freely from a building takes 5sec to reach at the ground a) What is the height of the building? b) Find the speed of the stone when it reaches at ground​

Answer 1

Height = 122.5 m

Speed = 49 m/s²

Step-by-step explanation:

Thanks for the question.

We will use second equation of motion.

We know, u = 0 (body falls from rest)

t = 5 (given)

a = 9.8 m/s² (acceleration due to gravity)

s = ut + 0.5 at²

s = 0.5 x 9.8 x 25 = 122.5

So, the height of the building is 122.5 m.

Now, v = u + at

v = 0 + 9.8 x 5 = 49 m/s²

Cheers