1 Answer

Kevin MOLCARD · Answer 1 · 2024-12-27T11:12:21+0000

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As we know, exterior angle of a triangle is equal to sum of the two internal angles that are not in linear pair with it (or opposite to that angle)

So, by using this property :

$\qquad \sf  \dashrightarrow \: 4x + 80 \degree = 2x\degree + 108\degree$

$\qquad \sf  \dashrightarrow \: 4x - 2x \degree = 108\degree - 80\degree$

$\qquad \sf  \dashrightarrow \: 2x \degree = 28\degree$

$\qquad \sf  \dashrightarrow \: x = (28 / 2)\degree$

$\qquad \sf  \dashrightarrow \: x = 14\degree$

Angle Q is equal to :

$\qquad \sf  \dashrightarrow \: 2x$

$\qquad \sf  \dashrightarrow \: 2 * 14 \degree$

$\qquad \sf  \dashrightarrow \: 28 \degree$

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