Question

A contractor is installing a semicircular window with a radius of 3.5 feet.

A semi circle has a diameter connecting its endpoints. The radius is labeled three and five tenths feet.

Find the distance around the window. Use 227 for π. Explain your answer.

Enter the correct answers in the boxes.

Distance:
ft; Find the circumference of the complete circle, C=2πr.

C≈ $$
≈ _/_x_x_ft. The circumference of half the circle is about ___ft. The distance around the window also includes the straight base, so it is about ___ft.

Answer 1

Answer: Distance: 22.7x3.5=79.95 ft;

To find the distance around the window, we need to find the circumference of the complete circle, which is given by the formula C = 2πr.

In this case, the radius is 3.5 ft and π is approximately equal to 227.

So we can substitute these values in the formula: C = 2πr = 2(227)(3.5) = 79.95 ft.

Since the window is a semicircle, we only need half of the complete circumference to find the distance around it, so the distance around the window is about 39.975 ft.

However, the distance around the window also includes the straight base, so it is about 40 ft.

Explanation: