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Q2: Determine whether the graphs of each pair of equations are parall

perpendicular or neither.
1. y = 3x + 4
y = 3x + 7
3. y = 2x-5
y = 5x -5
5. y = 3/5x - 3
5y = 3x - 10
7. y = 7x + 2
x + 7y=8
2. y = -4x+1
4y = x + 3
4. y=-1/3x + 2
y = 3x - 5
6. y = 4
4y = 6
8. y = 5/6x - 6
x + 5y = 4

Q2: Determine whether the graphs of each pair of equations are parall perpendicular-example-1
User Luke Bream
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1 Answer

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Answer:

The graphs of y = 3x + 4 and y = 3x + 7 are parallel because their slopes are the same (3).

The graphs of y = 2x - 5 and y = 5x - 5 are neither parallel nor perpendicular because their slopes are not the same (2 and 5).

The graphs of y = 3/5x - 3 and 5y = 3x - 10 are neither parallel nor perpendicular. The first equation is not in slope-intercept form, and the second equation is not in standard form.

The graphs of y = 7x + 2 and x + 7y = 8 are neither parallel nor perpendicular. The first equation is in slope intercept form, but the second equation is not.

The graphs of y = -4x + 1 and 4y = x + 3 are perpendicular because the product of their slopes is -1.

The graphs of y = -1/3x + 2 and y = 3x - 5 are neither parallel nor perpendicular. The slopes are -1/3 and 3, which are not the same, so the lines are not parallel, and their product is not -1, so the lines are not perpendicular.

The graph of y = 4 is a horizontal line and the graph of 4y = 6 is not a function. So, they are neither parallel nor perpendicular.

The graphs of y = 5/6x - 6 and x + 5y = 4 are neither parallel nor perpendicular. The first equation is in slope intercept form, but the second equation is not.

Explanation:

User Vhadalgi
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