Question

Inga is solving 2x2 + 12x – 3 = 0. Which steps could she use to solve the quadratic equation? Select three options. 2(x2 + 6x + 9) = 3 + 18 2(x2 + 6x) = –3 2(x2 + 6x) = 3 x + 3 = Plus or minus StartRoot StartFraction 21 Over 2 EndFraction EndRoot 2(x2 + 6x + 9) = –3 + 9

Answer 1

Inga could factor the quadratic equation: 2x^2 + 12x - 3 = 0 -> 2(x^2 + 6x + (-3/2)^2) = 0

Inga could use the quadratic formula: x = (-b +/- sqrt(b^2 - 4ac)) / 2a, where a = 2, b = 12 and c = -3.

Inga could complete the square: 2x^2 + 12x - 3 = 0 -> 2(x^2 + 6x + 9) - 18 = 0 -> 2(x + 3)^2 - 18 = 0

Explanation: