Question

For a moving object, the force acting on the object varies directly with the object's acceleration. When a force of acts on a certain object, the acceleration of the object is 4/ms2 . If the force is changed to 15n , what will be the acceleration of the object?

Answer 1

Explanation:

Given that for a moving object force acting on the object varies directly with the object's acceleration. If F be the force and a be the acceleration, then ;

`\implies \rm F \propto a\\`

`\implies \rm F = ka \dots (1)\\`

Initially, let force be F and the acceleration is 4m/s² .So

`\implies \rm F = k (4) \\`

If the force is increased 15 times then ,

`\implies \rm 15F = k a \dots (2) \\`

Divide (1) and (2) ,

`\implies \rm (F)/(15F)=(k(4))/(k(a))\\`

simplify,

`\implies \rm (1)/(15)=(4)/(a)\\`

`\implies \rm a = (4)/(15) m/s^2`

And we are done!

-Rishabh