Answer:
Step-by-step explanation:
The half-life of Iron-59 is 44.5 days, which means that every 44.5 days, half of the remaining Iron-59 will decay. To calculate how much of a 4.0mg sample will remain after 133.5 days, we can use the formula:
A = A0 * (1/2)^(t/T)
Where A is the remaining amount, A0 is the initial amount (4.0mg), t is the time elapsed (133.5 days), and T is the half-life (44.5 days).
Plugging in the values, we get:
A = 4.0 * (1/2)^(133.5/44.5)
A = 4.0 * (1/2)^3
A = 4.0 * (1/8)
A = 0.5 mg
So after 133.5 days, 0.5mg of the 4.0mg sample will remain.