Question

A 200.0 mL sample of 0.0500 M K₂CO, solution is

added to 300.0 mL of 0.100 M AgNO, solution. Silver
carbonate precipitates. The concentration of silver ion,
Ag, in solution after reaction is

Answer 1

Step-by-step explanation:

from;

K2CO + 2AgNO = 2KNO + Ag2CO

Data

V(K2CO)= 200.0mL =0.2L

[K2CO]=0.0500M

V(AgNO)=300.0mL =0.3L

[AgNO]= 0.100M

For that of K2CO

from, amount of subtance = [ K2CO] × V( K2CO)

n(K2CO)= 0.0500× 0.2

= 0.10 mol

For that of AgNO

from, amount of subtance = [ AgNO] × V( AgNO)

n(AgNO)= 0.100× 0.3

= 0.30 mol

The amount of Ag+ ions present will be;

*0.30-0.1/2)

(0.30- 0.05)

n(Ag+)= 0.25mol