196k views
0 votes
I needs help now pls

2C2H2(g) + 5O2(g) → 4CO2(g) + 2H2O(g)

This is a balanced equation for the combustion of acetylene (C2H2). How many grams of acetylene(C2H2 ) are required to produce 1.0 moles of CO2?

5.0 grams


0.20 grams


13.0 grams


10.0 grams

User NoSixties
by
7.5k points

1 Answer

4 votes
2.0 grams of acetylene (C2H2) are required to produce 1.0 moles of CO2. This is because the balanced equation states that for every 2 moles of acetylene (C2H2) that react, 4 moles of CO2 are produced. Therefore, 1.0 moles of CO2 requires 2.0 moles of acetylene (C2H2). Since 1 mole of any substance is equal to its molecular weight in grams, 2.0 grams of acetylene (C2H2) are required to produce 1.0 moles of CO2 making the answer 10.0 grams.
User Sandeep Dhull
by
7.8k points