Answer: hello person.
This is a system of equations problem that can be solved using substitution.
Let x be the number of pennies
Therefore the number of dimes is also x.
The number of quarters is 44 - 2x
The total value of the pennies is x * 0.01 = $0.01x
The total value of the dimes is x * 0.1 = $0.1x
The total value of the quarters is (44 - 2x) * 0.25 = $11 - 0.5x
Now we know that the total value is $0.01x + $0.1x + $11 - 0.5x = $3.59
So we can write the equation:
0.01x + 0.1x + 11 - 0.5x = 3.59
Now we can solve for x
0.6x + 11 = 3.59
0.6x = -7.41
x = -12.35
We know that x is the number of pennies and dimes. Since it is not a whole number, it is not possible.
We can think of another approach, assuming that x is the number of dimes and pennies, and y is the number of quarters.
x + y = 44
0.1x + 0.25y = 3.59
Now we can solve for x and y by substitution method.
x = 44 - y
0.1(44 - y) + 0.25y = 3.59
4.4 - 0.1y + 0.25y = 3.59
4.4 = 0.35y + 3.59
0.81 = 0.35y
y = 2.3
x = 44 - 2.3 = 41.7
We know that x and y must be whole numbers. Since x and y are not whole numbers it is not possible.
Hence, there is no possible number of coins for Carlos to have for the given scenario.
Explanation: