Question

I need Help please hurry

Answer 1

Let's consider what the question asks for:

--> domain and range, x-intercept, y-intercept of the equation

Let's find the domain:

--> the only range of x-values that will make this equation 'untrue'

--> is when the function inside the square root becomes negative

--> as a square root cannot have a negative value inside it

`x+8\geq 0\\x\geq -8\\\\\text{Our domain is therefore [-8}`,∞)

Let's find our range:

--> the function doesn't have any limitations vertically

`\text{Our range is therefore}` (-∞,∞)

Our x-intercept

--> is when the y-value is zero

`0=-2√(x+8) \\√(x+8) =0\\x+8=0\\x=-8`

`\text{Our x-intercept is therefore -8}`

Our y-intercept:

--> is when the x-value is zero

`y=-2√(x+8) \\y=-2√(0+8) \\y=-2√(8) \\y=-2*2√(2) \\y=-4√(2)`

`\text{Our y-intercept is therefore }-4√(2)`

Answer:

Domain: [-8, ∞)

Range: {-∞,∞)

X-intercept is -8

Y-intercept is
`-4√(2)`