Question

1. How many grams of Na2SO4, will be produced if 2.9 L of HCl are also produced at a

temperature of 98°C and a pressure of 1.13 atm?
2.If 3.4 L of H₂SO4 are reacted, how many liters of HCI would be produced?

Answer 1

Answer:he balanced chemical equation is

H

2

​

SO

4

​

+2NaOH→Na

2

​

SO

4

​

+2H

2

​

O

Thus, 1 mole H

2

​

SO

4

​

will react with 2 moles of NaOH.

The molecular weights of H

2

​

SO

4

​

and NaOH are 98 g/mol and 40 g/mol respectively.

The mass is divided with molecular weight to obtain the number of moles.

The number of moles of H

2

​

SO

4

​

=

98

98

​

=1 mole.

The number of moles of NaOH =

40

40

​

=1 mole.

Thus 1 mole of H

2

​

SO

4

​

and 1 mole of NaOH are present.

0.5 mole of H

2

​

SO

4

​

will react with 1 mole of NaOH.

Thus H

2

​

SO

4

​

is the excess reagent and NaOH is limiting reactant.

1 mole of H

2

​

SO

4

​

will produce 1 mole of Na

2

​

SO

4

​

Hence, 0.5 mole of H

2

​

SO

4

​

will produce 0.5 mole of Na

2

​

SO

4

​

The molecular weight of Na

2

​

SO

4

​

is 142 g/mol.

The mass of Na

2

​

SO

4

​

produced is 0.5×142=71 g.

Step-by-step explanation: