The balanced equation for the combustion of acetylene (C₂H₂) is provided as 2C₂H₂(g) +50₂(g) → 4CO₂(g) + 2H₂O(g)
This equation states that 2 moles of acetylene (C₂H₂) and 5 moles of oxygen (O₂) are needed to produce 4 moles of carbon dioxide (CO₂) and 2 moles of water (H₂O).
To calculate the number of grams of acetylene (C₂H₂) required to produce 1.0 moles of CO₂, we can use the equation for the molar mass of acetylene (C₂H₂) and divide it by the number of moles of CO₂ produced.
The molar mass of acetylene (C₂H₂) is 26.03 g/mol
0.20 grams of acetylene is required to produce 1.0 mole of CO₂