Question

write the equation of a line that passes through the point (12, 5) and has a slope of -3y+5=-3(x+12)y+12=-3(x-5)y-12=-3(x+5)y-5=-3(×-12)

Answer 1

Point slope form:

y-y1 = m (x-x1)

where;

m= slope = -3

(x1,y1) points of the line. (12,5)

Replacing:

y-5 = -3 (x-12)