Question

May I please receive assistance on this problem? I would greatly appreciate it!

Answer 1

Given the following question:

`\begin{gathered} (m-2)/(m-1) \\ \end{gathered}`
`\begin{gathered} (m-2)/(m-1) \\ \text{ Option C:} \\ (m^2-m-2)/(m^2-1) \\ \text{ Factor} \\ m^2-m-2=(m+1)(m-2) \\ (m^2-m-2)/(m^2-1)=(\left(m+1\right)\left(m-2\right))/(m^2-1) \\ (\left(m+1\right)\left(m-2\right))/(m^2-1) \\ m^2-1=(m+1)(m-1) \\ (m+1)(m-1)=(\left(m+1\right)\left(m-2\right))/(\left(m+1\right)\left(m-1\right)) \\ \text{ Cancel cf} \\ =((m-2))/((m-1))x \end{gathered}`

Your answer is option C.