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12 years ago, a mother was twice as old as her son. their present age are in the ratio of 14:9. find their present ages.​

1 Answer

6 votes

Answer:

The presents age of the mom is 42 years old, and of the son is 27 years old.

Explanation:

This question can be solved using a system of equations.

I am going to say that:

The mothers age is x.

The son's age is y.

12 years ago, a mother was twice as old as her son.

This means that:


x - 12 = 2(y - 12)


x = 2y - 24 + 12


x = 2y - 12

Their present age are in the ratio of 14:9.

This means that:


(x)/(y) = (14)/(9)


14y = 9x

Since
x = 2y - 12


14y = 9(2y - 12)


18y - 108 = 14y


4y = 108


y = (108)/(4)


y = 27


x = 2*27 - 12 = 54 - 12 = 42

The presents age of the mom is 42 years old, and of the son is 27 years old.

User Kardaj
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