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Solve (2/6)^12/7 (That's two sixths to the power of twelve sevenths.)

1 Answer

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(2/6)^12/7
(1/3)^12/7
7 square root (1/3)^12
7 square root (1/3^12)
1/ 7square root 3^12
1/3^7 square root 3^5
7 square root 3^2/9
answer = 7square root 9/9
User Eugene Tsakh
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