Solve (2/6)^12/7 (That's two sixths to the power of twelve sevenths.)

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asked Nov 21, 2024 193k views

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Eugene Tsakh · Answer 1 · 2024-11-25T02:16:14+0000

(2/6)^12/7
(1/3)^12/7
7 square root (1/3)^12
7 square root (1/3^12)
1/ 7square root 3^12
1/3^7 square root 3^5
7 square root 3^2/9
answer = 7square root 9/9

Solve (2/6)^12/7 (That's two sixths to the power of twelve sevenths.)

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