Answer: X= 72°
Here if we see the figure is not labelled so I am assuming it to A,B,C AS MAIN TRIANGLE and BD bisector of angle ABC.
We have to find out that angle DBC.
ANGLE CAB = ANGLE DBA
Hence Angle CDB = ANGLE CAB + ANGLE DBA
27° + 27° = CDB = 54° = ACB ( if sides are equal then opposite angles are also equal.)
so required angle x = 180° - 54° - 54° ( sum of angle of triangle equals 180)
so x= 72°