Question

A line is perpendicular to y = -2x + 5

and intersects the point (-4, 2). What is
the equation of this perpendicular line?
y = ?/?/x + ?
Hint: Use the Point-Slope Form: y - y₁ = m(x - X1)
Then write the equation in slope-intercept form.
Enter

Answer 1

Answer: the equation of the line that is perpendicular to y = -2x + 5 and passes through the point (-4, 2) is y = (1/2)x + 5.

Explanation:

The slope of the line that is perpendicular to y = -2x + 5 is the negative reciprocal of the slope of y = -2x + 5, which is -2. The negative reciprocal of -2 is 1/2.

To find the equation of the line that is perpendicular to y = -2x + 5 and passes through the point (-4, 2), we can use the Point-Slope Form: y - y₁ = m(x - X1)

y - 2 = (1/2)(x + 4)

Simplifying, we get:

y = (1/2)x + 5

So the equation of the line that is perpendicular to y = -2x + 5 and passes through the point (-4, 2) is y = (1/2)x + 5.