Answer:
Explanation:
The equation x^2 + kx + 5 = 0 has real roots if and only if the discriminant b^2 - 4ac is greater or equal to zero.
In this case, the discriminant is k^2 - 415 = k^2 - 20.
So we know that k^2 - 20 >= 0
therefore k >= sqrt(20) or k <= -sqrt(20)
Two positive values of k are:
k = sqrt(20)
k = sqrt(20) + n, where n is an integer greater than 0
Please note that this is an algebraic solution and doesn't account for any other possibilities that the problem or context may have.