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Write the first 4 terms of the sequence defined by the given rule: f(n)=2n^2+4

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Answer: The sequence is defined by the rule f(n) = 2n^2 + 4.

To find the first 4 terms of the sequence, we need to plug in the values of n into the rule and calculate f(n) for each value of n.

n = 1: f(1) = 2(1)^2 + 4 = 2 + 4 = 6

n = 2: f(2) = 2(2)^2 + 4 = 8 + 4 = 12

n = 3: f(3) = 2(3)^2 + 4 = 18 + 4 = 22

n = 4: f(4) = 2(4)^2 + 4 = 32 + 4 = 36

So, the first 4 terms of the sequence are 6, 12, 22, 36

Explanation:

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