Question

Magan and his children went into a grocery store and he bought $9 worth of apples and bananas. Each apple costs $1 and each banana costs $0.50. He bought 6 more bananas than apples. By following the steps below, determine the number of apples, x and the number of bananas, y that Magan bought.

Answer 1

Magan bought 4 apples and 10 bananas, denoted by x and y respectively, based on the equation y = x + 6 and the total cost of 1*x + 0.5*y = $9.

Step-by-step explanation:

To solve the question involving Magan's purchase of apples and bananas, we need to set up two equations based on the information provided. The cost of the apples is $1 each, the bananas cost $0.50 each, and the total amount spent is $9.

Let's denote the number of apples bought by x, and the number of bananas by y. The problem states that Magan bought 6 more bananas than apples, giving us the first equation y = x + 6. The second equation represents the total amount spent: 1*x + 0.5*y = 9.

Substituting the first equation into the second gives us 1*x + 0.5*(x + 6) = 9. Simplifying, we get 1.5*x + 3 = 9. Solving for x, we find x = (9 - 3) / 1.5 = 4. Therefore, Magan bought 4 apples. Plugging this value into our first equation, y = 4 + 6 = 10, we find that Magan bought 10 bananas.

Answer 2

Answer: 4 apples 10 banana

Step-by-step explanation: 4 apples is 4 dollars + 1/2 of 10 which is 5 = 9

to figure this out I start out adding 1 apple and 1 banana to each side starting with 0 apples and 6 bananas until I got to 9 dollars worth of fruit