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Find an equation of the line L. L is perpendicular to y=-2x. points (3,-6)

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Answer:

Explanation:

If L is perpendicular to the line y = -2x, then the slope of L is the negative reciprocal of -2. So the slope of L is 1/2.

Now we know that the line L goes through the point (3,-6), so we can use the point-slope form of a linear equation to find the equation of L.

The point-slope form of a linear equation is: y - y1 = m(x - x1)

where (x1, y1) is a point on the line, and m is the slope of the line.

Here, (x1, y1) = (3, -6) and the slope of the line is m = 1/2, so the equation is:

y - (-6) = (1/2)(x - 3)

Simplifying this gives us the final equation of the line L:

y = (1/2)x - 3

Please note that this is one of the possible solutions and it depends on the problem or context if this is the correct one.

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