Question

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A 12.6 kg box is being pushed to the right across the floor with an applied force of 54 N friction opposes the motion with a force of 37 N the force caused by the earth is balanced by the force cased by the floor.

Calculate the weight of the box

what are the givens

what is the equation
how to solve

Then draw a free body diagram that includes all the forces acting on the box with labels numbers and units i (if possible)

what is the net force acting on the box
finally what is the acceleration of the box what are the givens, equation and how to solve

Answer 1

To summarize:

The weight of the box is 123.88 NThe net force acting on the box is 17 N (to the right)The acceleration of the box is 1.35 m/s^2 (to the right)

And the Free Body Diagram is:

`[box]^||54 N (applied force)|||v37 N (friction)`

Step-by-step explanation:

Given:

• Mass of the box: 12.6 kg
• Applied force: 54 N

• Frictional force opposing motion: 37 N

To calculate the weight of the box:

• The weight of an object is equal to its mass multiplied by the acceleration due to gravity (g).
• The weight of the box is 12.6 kg * 9.8 m/s^2 = 123.88 N (approx).

Free Body Diagram:

`[box]^||54 N (applied force)|||v37 N (friction)`

Net force acting on the box:

• The net force is the vector sum of all the forces acting on the object.
• In this case, the net force is 54 N - 37 N = 17 N (to the right).

To calculate the acceleration of the box:

• The acceleration of an object is equal to the net force acting on it divided by its mass.
• The acceleration of the box is 17 N / 12.6 kg = 1.35 m/s^2 (to the right).

Answer 2

The weight of the box is given by the formula: weight = mass x gravity. The mass of the box is 12.6 kg and the gravitational acceleration is 9.8 m/s^2. Therefore, the weight of the box is 12.6 x 9.8 = 123.48 N.
The givens in this problem are:
Mass of the box: 12.6 kg
Applied force: 54 N
Frictional force: 37 N
Gravitational acceleration: 9.8 m/s^2
The equation to find the net force acting on the box is: net force = applied force - frictional force. In this case, the net force is 54 N - 37 N = 17 N.
To solve for the net force, you would subtract the frictional force from the applied force. In this case, 54 N - 37 N = 17 N.
A free body diagram for this problem would show the box with an arrow pointing to the right representing the applied force of 54 N, an arrow pointing to the left representing the frictional force of 37 N, and an arrow pointing downward representing the weight of the box of 123.48 N
The net force acting on the box is 17 N
To find the acceleration of the box, use the equation: force = mass x acceleration. In this case, 17 N = 12.6 kg x acceleration. To solve for acceleration, divide both sides by 12.6 kg. The acceleration of the box is 1.35 m/s^2.