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The hypotenuse of a right triangle os 13.0 and one leg is 2.0 units shorter than the other. Find the dimensions of the figure (rounded to the nearest tenth).

User Zeckdude
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Answer:Let, one leg be x units.

since the other leg is 9.0 units shorter than the other,

the measure of the other leg =x-9

hypotenuse =13.0 units

According to Pythagorean theorem, the square of the hypotenuse is equal to the sum of squares of the other two sides.

x^2 +(x-9)^2 =13^2

x^2 + x^2 -18x +81 = 169

2x^2-18x-88=0

Divide the whole equation by 2

x^2 - 9x -44 =0

Let's use the quadratic formula to find the roots.

formula: x= [-b ± sqrt(b^2-4*a*c)]/2*a

a=1 b=-9 c=-44

x= [9±sqrt(81+176)]/2

=[9±sqrt(257)]/2

=[9±16.03]/2

=25.03/2 or -7.03/2

length of a triangle cannot be negative,

Therefore, x=25.03/2 =12.52

one leg =12.5 units

other leg =12.52-9 =3.5 units

Explanation:

User Vrajesh Doshi
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