Answer:
The equation of the line can be written in slope-intercept form as y = mx + b, where m is the slope of the line and b is the y-intercept.
To find the equation of the line that passes through the point (-2, 1) and has a slope of 1/2, we can use the point-slope form of the equation of a line. The point-slope form is:
y - y1 = m(x - x1)
where (x1, y1) is a point on the line and m is the slope of the line.
So, using the point (-2, 1) and the slope of 1/2, we can write the equation of the line as:
y - 1 = (1/2)(x + 2)
Which can be re-arranged to the slope-intercept form
y = (1/2)x + (3/2)
Therefore, the equation of the line that passes through the point (-2, 1) and has a slope of 1/2 is y = (1/2)x + (3/2)
This equation can be used to find the y-coordinate of any point on the line, given its x-coordinate.