Final answer:
The individual will deposit $958 into the retirement account each month, which will grow to approximately $2,625,858 after 30 years due to compound interest. The total contribution will be $344,880, and the total growth will be around $2,280,978. With the additional $100 monthly saving, the total would increase to approximately $2,900,396 after 30 years.
Step-by-step explanation:
To calculate the monthly retirement contribution, we take 10% of the annual salary of $115,000 and divide by 12 (the number of months in a year).
Monthly deposit = ($115,000 * 0.10) / 12 = $11,500 / 12 = $958.33
Rounded to the nearest dollar, the monthly deposit is $958 per month.
Now, let's calculate the future value of the retirement account after 30 years using the compound interest formula:
FV = P * ((1 + r/n)^(nt))
Where:
FV = future value of the investment
P = principal amount (monthly deposit)
r = annual interest rate (expressed as a decimal)
n = number of times the interest is compounded per year
t = number of years
We assume monthly compounding (n = 12) and an annual interest rate of 7% (r = 0.07):
FV = $958 * ((1 + 0.07/12)^(12*30))
FV ≈ $958 * ((1 + 0.00583)^360)
FV ≈ $958 * (1.00583^360)
FV ≈ $958 * 7.6123
FV ≈ $7294.05 per month
Total contributed over 30 years: $958 * 12 * 30 = $344,880
Total expected in the account after 30 years: $7294.05 * 12 * 30 = $2,625,858
Total growth/interest earned: $2,625,858 - $344,880 = $2,280,978
If an additional $100 is saved each month, the new monthly deposit is $958 + $100 = $1,058.
With the new monthly deposit:
FV = $1,058 * ((1 + 0.07/12)^(12*30))
FV ≈ $1,058 * 7.6123
FV ≈ $8056.83 per month
Total expected in the account after 30 years with the additional savings: $8056.83 * 12 * 30 = $2,900,396