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Need help with this problem-example-1
User Yulia V
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Explanation:

f(x) = x² + 5 g(x) = x + 4

for f(g(x)) or (f○g)(x) we take the expression of g and place it everywhere in the expression of f where x is mentioned.

so, (x + 4) goes into (x² + 5) giving us

((x + 4)² + 5) = x² + 8x + 16 + 5 = x² + 8x + 21

so, (2) is the correct answer.

8.

the same principle

f(x) = 2x + 9 g(x) = (x - 9)/2

just here we take f and put it into g :

g(f(x)) = ((2x + 9) - 9)/2 = 2x/2 = x

so,

(a) g(f(15)) = 15

(b) g(f(-3)) = -3

(c) g(f(x)) = x

to verify e.g. (a) we use x = 15 in f(x)

f(15) = 2×15 + 9 = 30 + 9 = 39

and then we use this result as new x = 39 in g :

g(39) = (39 - 9)/2 = 30/2 = 15

correct.

User Gerbus
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