Question

Triangle M N O is shown. Angle O N M is a right angle. Angle N O M is 40 degrees and angle L M N is 50 degrees.

Given right triangle MNO, which represents the value of cos(M)?

StartFraction O N Over M N EndFraction
StartFraction M N Over M O EndFraction
StartFraction O N Over M O EndFraction
StartFraction M N Over O N EndFraction

Answer 1

it is b

Explanation:

Answer 2

Given:

In triangle MNO, angle ONM is a right angle. Angle NOM is 40 degrees and angle LMN is 50 degrees.

To find:

The value of cos(M).

Solution:

In a right angle triangle,

`\cos \theta=(Base)/(Hypotenuse)`

Draw a diagram using the given information.

In triangle MNO, angle ONM is a right angle so its opposite side MO is the hypotenuse. For vertex M, MN is the base of the triangle. So,

`\cos (M)=(MN)/(MO)`

Therefore, the correct option is B.