Question

Find the perimeter of (triangle) ABC with vertices A(-2, 3), B(3,-3), and C(-2, -3).​ Part A calculate the length of each side.

Part B Calculate the perimeter of abc

Answer 1

Check the picture below.

so we just need to find the distance for AB and sum them all up for the perimeter

`~~~~~~~~~~~~\textit{distance between 2 points} \\\\ A(\stackrel{x_1}{-2}~,~\stackrel{y_1}{3})\qquad B(\stackrel{x_2}{3}~,~\stackrel{y_2}{-3})\qquad \qquad d = √(( x_2- x_1)^2 + ( y_2- y_1)^2) \\\\\\ AB=√((~~3 - (-2)~~)^2 + (~~-3 - 3~~)^2) \implies AB=√((3 +2)^2 + (-3 -3)^2) \\\\\\ AB=√(( 5 )^2 + ( -6 )^2) \implies AB=√( 25 + 36 ) \implies AB=√( 61 ) \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{\LARGE Perimeter}}{6~~ + ~~5~~ + ~~√(61)} ~~ \approx ~~ \text{\LARGE 18.81}`