A 400 Kg car has 1.8 x 10^5 J of kinetic energy. How fast is it moving?

asked Aug 3, 2024 176k views

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4 votes

Step-by-step explanation:

$e = (1)/(2) m {v}^(2) \\ 1.8 * {10}^(5) = (400/ 2) {v}^(2) \\ v = \sqrt{1.8 * {10}^(5) / (400 / 2)}$

Sleepyup answered Aug 9, 2024

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