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If the line through the points (1,2) and (1,a) is parallel to 6x+2y=-2, what is the value of a?

User Codium
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Two lines are parallel if their slopes are equal. To find the slope of the line through the points (1,2) and (1,a), we can use the formula:

(y2 - y1) / (x2 - x1) = (a - 2) / (1 - 1) = a - 2

To find the slope of the line 6x + 2y = -2, we can rewrite it in slope-intercept form (y = mx + b) by isolating y:

2y = -6x - 2

y = -3x - 1

So the slope of this line is -3.

Since the line through the points (1,2) and (1,a) is parallel to 6x + 2y = -2, we know that the slopes must be equal. Therefore:

a - 2 = -3

Solving for a:

a = -1

So the value of a is -1.

User Berlin Brown
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