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3 votes
Solve for x and y.

2x + 5y = 8
4x + 3y = 2
Ax = 2, y = -2
Bx = 1, y = 2
Cx = -1, y = 2
Dx = -2, y =
4

2 Answers

5 votes

Answer:

c

Explanation:

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User David West
by
7.3k points
5 votes

Answer:

C) x = -1, y = 2

Explanation:

Given system of linear equations:


\begin{cases}2x + 5y = 8\\4x + 3y = 2\end{cases}

Multiply the first equation by -2:


\implies -2 \cdot 2x -2 \cdot 5y=-2 \cdot 8


\implies -4x-10y=-16

Add this to the second equation to eliminate x:


\begin{array}{crcrcr}& 4x & + & 3y & = & 2\\+&(-4x & - &10y&=&-16\\\cline{2-6}&&-&7y&=&-14\end{array}

Solve for y:


\implies -7y=-14


\implies (-7y)/(-7)=(-14)/(-7)


\implies y=2

Substitute the found value of y into one of the equations and solve for x:


\implies 2x+5(2)=8


\implies 2x+10=8


\implies 2x=-2


\implies x=-1

Therefore the solution to the given system of linear equations is:

  • x = -1, y = 2
User Mimoza
by
7.3k points