Answer:
Explanation:
Given-: Y= -X+1 (1)
3X-Y=3 (2)
we will put the value of Y from equation (1) in equation (2)
3X-(-X+1)=3
3X+X-1=3
4X-1=3
Taking -1 to R.H.S
4X=3+1
4X=4
X=4/4
X=1
Now put the value of X in equation (1)
Y=-X+1
Y=-1+1
Y=0
So the option will be B (1,0)