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Calculate the mass in grams in a sample containing 2.40×10^23 S03 molecules.

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Answer: 31.2 g

Explanation: Given,

2.40 x 10^23 molecules of SO3

number of moles (n) = given number of molecules / total number of molecules

n = 2.4 x10^23/ 6.023 x 10^23

n = 0.39 moles

mass = molecular mass x number of moles(n)

mass in grams = 80 (Molecular mass of SO3) x 0.39

mass in grams = 31.2 g

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