Question

A pendulum has a period of 6.98s. Calculate the length of the pendulum. Use

9.8m/s^2 for gravity. *

Answer 1

Length, l = 0.126 meters.

Step-by-step explanation:

Given the following data;

Period = 6.98s

Acceleration due to gravity, g = 9.8m/s²

To find the length, l;

`Period, T = 2 \pi \sqrt {lg}`

Substituting into the equation, we have;

`6.98 = 2*3.142 \sqrt {l*9.8}`

`6.98 = 6.284 \sqrt {9.8l}`

`\frac {6.98}{6.284} = \sqrt {9.8l}`

`1.1108 = \sqrt {9.8l}`

Taking the square of both sides

`1.1108^(2) = 9.8l`

`1.2339 = 9.8l`

`l = \frac {1.2339}{9.8}`

Length, l = 0.126m.