Question

Find the equation of a line that is parallel to y=13x−5 and passes through the point (3,−2).

Give your answer in the form y=mx+b.

Answer 1

y = 13x - 41

Explanation:

Parallel lines always have the same slope since

`m_(2)=m_(1)`

Thus, the slope of the second line is m = 13.

We can find the y-intercept of the line by plugging in the points for x and y, 13 for m, and solving for b:

`-2=13(3)+b\\-2=39+b\\-41=b`