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Write an equation in slope-intercept form the line that is perpendicular to the line y=1/4x-9 and passes through (1,1)

User Krzysztof
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1 Answer

5 votes

Explanation:

since we got a point and actually the slope, we can start with the point-slope form and transform.

you know that the slope-intercept form is

y = ax + b

"a" is the slope, "b" is the y-intercept.

we see therefore, that the slope of the given line is 1/4.

a perpendicular slope (90°) turns the slope fraction upside-down and flips the sign.

so, the perpendicular slope is -4/1 = -4.

the point-slope form is

y - y1 = a(x - x1)

"a" is again the slope (for the new line this is -4), (x1, y1) is a given point. in our case (1, 1).

so, we get

y - 1 = -4(x - 1)

we transform by simplifying :

y - 1 = -4x + 4

y = -4x + 5

y = -4x + 5

is the perpendicular line in slope-intercept form that passes through (1, 1).

User Chris Hynes
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8.4k points

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