To find the mass of Nitrogen (N) in 0.464 grams of N2H4 (hydrazine), we need to use the molar mass of N2H4 and the proportion of Nitrogen in the compound.
First, the molar mass of N2H4 is (14.01 + 2(14.01) + 4(1.01)) = 32.05 g/mol.
Next, we know that the proportion of Nitrogen in N2H4 is 2 moles of Nitrogen to 1 mole of N2H4, or 2/1.
So, to find the mass of Nitrogen in 0.464 grams of N2H4, we can use the following formula:
Mass of Nitrogen = (mass of N2H4) x (proportion of Nitrogen) / (molar mass of N2H4)
Plugging in the values:
Mass of Nitrogen = (0.464 g) x (2/1) / (32.05 g/mol)
Mass of Nitrogen = 0.028 grams
Therefore, the mass of Nitrogen in 0.464 grams of N2H4 is 0.028 grams.