Question

The area of a rectangular room is 750 square feet. The width of the room is 5 feet less than the length of the room. Which equations can be used to solve for y, the length of the room? Select three options. y(y + 5) = 750 y2 – 5y = 750 750 – y(y – 5) = 0 y(y – 5) + 750 = 0 (y + 25)(y – 30) = 0

Answer 1

y(y-5) =750 squared-feet

Explanation:

`{y}^(2) - 5y = 750 \\ 750 - y(y - 5) = 0 \\ (y + 25)(y - 30) = 0`