Question

. This semester there are 67 students performing in the middle school's

production of "Beauty and the Beastly." Of these students, 49 are 7th and 8th
graders. Write a proportion and solve for s, the percent of 6th grade students
that are in the play. Round your answer to the nearest tenth of a percent.

Answer 1

We know that there are 67 students performing in the middle school's production of "Beauty and the Beastly." and 49 of them are 7th and 8th graders.

We can write a proportion to find the percent of 6th grade students in the play:

6th grade students / Total students = s / 100

We know that 49 of the students are 7th and 8th graders, so the number of 6th grade students is 67 - 49 = 18.

Now we can substitute the values in the proportion and solve for s:

18 / 67 = s / 100

To find s, we can cross-multiply and divide:

18 * 100 = 67 * s

1800 = 67 * s

s = 1800 / 67

s = 26.87

Rounding to the nearest tenth of a percent: 26.9 %

So, the percent of 6th grade students that are in the play is 26.9%.