Question

Solve the system of equations by multiplying first. Enter the solution as an ordered pair.

4x+8y=40
3x-2y = 14

Answer 1

We can start by multiplying the first equation by 3:

12x + 24y = 120

Then we can multiply the second equation by 4:

12x - 8y = 56

Now, we have:

12x + 24y = 120

12x - 8y = 56

If we subtract the first equation from the second equation:

32y = 64

y = 64/24

y = 2

Now that we know the value of y, we can substitute it back into one of the original equations to find the value of x.

Let's use the first equation:

4x+8(2) = 40

4x+16 = 40

4x = 24

x = 24/4

x =6

So, the solution of the system of equations is x = 6, y = 2.

Answer 2

14

Explanation: