Given the system of equation
-2x + 2y = - 16 ..... *5
5x - 3y = 28 ....... *2
Use elimination method
Multiply equation 1 by 5 and equation 2 by 2
The equation becomes
-10x + 10y = - 80 ..... 3
10x -6y = 56 ....... 4
add equation 3 from 4;
10y - 6y = -80+56)
4y = -80+56
4y = -24
y = -24/4
y = -6
Subsitute y = -6 into equation -2x + 2y = - 16 to get x
-2x + 2(-6) = - 16
-2x-12 = -16
-2x = -16+12
-2x = -4
x = -4/-2
x = 2
Hence y = -6 and x = 2