Question

Consider the unbalanced equation for the oxidation of aluminum._Al _O2 Right arrow. _Al2O3Which sequence of coefficients should be placed in the blanks to balance this equation

Answer 1

Answer: 4Al + 3O2 -> 2Al2O3

Step-by-step explanation:

What I did was:

The product has 3 oxygens while the reactant has 2. So if you multiply the reactant by 3 and the product by 2 then the amount of oxygens on both sides will be equal (both sides have 6)

Then since there are now 4 Al on the product sides after multiplying by 2 for the oxygen (2 Al2 = 4 Al), there must be 4 Al on the reactants side.