Question

If you dilute 175 ml of a 1.6 M solution of LiCl to 1.0 L , determine the new concentration of the solution

Answer 1

1) List the known quantities

Initial conditions

Concentration 1: 1.6 M

Volume 1: 175 mL

Final conditions

Volume 2: 1 L

Concentration 2: unknown

2) Set the equation

`C1*V1=C2*V2`

3) Convert units

Volume

1 L = 1000 mL

`mL=1\text{ }L*\frac{1000\text{ }mL}{1\text{ }L}=1000\text{ }mL`

4) Plug in the known quantities and solve for C2

`(1.6\text{ }M)*(175\text{ }mL)=C2*(1000\text{ }mL)`
`C2=\frac{(1.6\text{ }M)*(175\text{ }mL)}{(1000\text{ }mL)}`
`C2=0.28\text{ }M`

The new concentration is 0.28 M.

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